How will you convert ethyl chloride into (i) ethane (ii) n-butane?

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Solution

$i)$ Ethyl chloride reacts with $a l c . K O H$ to yeild ethene which on hydrogenation with Nickel gives ethane.
$C H_{3} C H_{2} C l E t h y l - c h l o r i d e a l c K O H - ---- \to - H C l C H_{2} = C H_{2} E t h e n e H_{2} / N_{i} - --- \to C H_{3} - C H_{3} E t h a n e$
$i i)$ Ethyl chloride can be converted to $n - b u t a n e$ by wurtz reaction.
$2 C H_{3} C H_{2} C l + 2 N a a n h y d r o u s - ----- \to e t h e r C H_{3} C H_{2} C H_{2} C H_{3} n - b u t a n e + 2 N a C l$ .

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