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Question

(i) A blue coloured compoud (A) on heating gives two products, (B) and (C).
(ii) A metal (D) is deposited on passing hydrogen through heated (B).
(iii) The solution of (B) in HCl on treatment with gives a choclate brown coloured precipitated of compound (E).
(iv) (C) turns lime water milky which disappears on continous passage of (C) forming a compound (F).
Identify (A) to (F) and give chemical equations for the reactions at steps (i) to (iv).

A
A is CuSO45H2O
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B
B is CuO
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C
C is SO2.
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D
F is Ca(HSO3)2
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E
all of these correct
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Solution

The correct option is E all of these correct
(i) A blue coloured compoud CuSO45H2O on heating gives two products, CuO and SO2.
CuSO45H2OCuO+SO2+(5H2O+12O2)
(ii) A metal Cu is deposited on passing hydrogen through heated CuO.
CuO+H2Cu+H2O
(iii) The solution of CuO in HCl on treatment with gives a choclate brown coloured precipitated of compound Cu2[Fe(CN)6].
CuO+2HClCuCl2+H2O
2CuCl2+K4[Fe(CN)6]Cu2[Fe(CN)6]+4KCl
(iv) SO2 turns lime water milky which disappears on continous passage of SO2 forming a compound Ca(HSO3)2
Ca(OH)2+SO2CaSO3milky+H2O
CaSO3+H2O+SO2Ca(HSO3)2

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