Question

I have a container that is 20cm tall and filled fully with water. The lift accelerates up at 10m/s/s. What is the pressure difference between the top surface of the water and the bottom of the container? Take density of water as 1kg/l.

• A. $2\times {10}^4$
• B. $8\times {10}^4$
• C. $4\times {10}^4$
• D. $16\times {10}^4$

Answer 1

The correct option is C $4\times {10}^4$

Since the container is accelerating up, effective g will be
g' = g+a = 10+10 = $20m/s^2$

The pressure difference from top to bottom will be
$h\rho g=0.2\times 1000\times 20$
$=4\times {10}^{4}Pa$