Question

$I$ mole of $N_2{H}_4$loses ten moles of electrons to form a new compound $Y$. Assuming that all nitrogen appears in the new compound, what is the oxidation state of $N$ and $Y$? (there is not change in the oxidation state of hydrogen).

• A. $-1$
• B. $-3$
• C. $+3$
• D. $+5$

Answer 1

The correct option is C $+3$

Here the answer is option C

$N_2{H}_4=Y+10e$

calculation of oxidation state of N in $N_2{H}_4$

$2x+4=0$

$x=-2$

The two nitrogen atoms will balance the charge of the $10e^{-}$

Hence oxidation state of N will increase by +5

$ie,-2to+3$