Question

I. $x^2+x-20=0$
II. $y^2-y-30=0$

• A. If $x>y$
• B. If $x\ge y$
• C. If $x<y$
• D. If $x\le y$
• E. $x=y$ or the relationship cannot be established.

Answer 1

The correct option is E $x=y$ or the relationship cannot be established.

Equation I:-
$x^2+x-20=0$
$\Rightarrow x^2+5x-4x-20=0$
$\Rightarrow x(x+5)-4(x+5)=0$
$\Rightarrow (x-4)(x+5)=0$
$\Rightarrow x=4,-5$

Equation II:-
$y^2-y-30=0$
$\Rightarrow y^2+6y-5y-30=0$
$\Rightarrow y(y+6)-5(y+6)=0$
$\Rightarrow y=5,-6$