Identify the correct order of solubility in aqueous medium :

C u S > Z n S > N a_{2} S

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Z n S > N a_{2} S > C u S

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N a_{2} S > C u S > Z n S

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N a_{2} S > Z n S > C u S

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Solution

The correct option is D $N a_{2} S > Z n S > C u S$
The correct order of solubility in aqueous medium is $N a_{2} S > Z n S > C u S$ .

The percentage ionic character in $N a_{2} S$ is maximum.

Hence, it undergoes hydration to a maximum extent.

Hence, it has a maximum solubility.

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The cell representation of the given reaction is:
Zn(s) + Cu²⁺ → Zn²⁺ + Cu(s)

The standard reducation potentials of

$Z n^{2 +} | Z n, C u^{2 +} | C u$ and $A g^{+} | A g$

are respectively -0.76, 0.34 and 0.8 V. The following cells were constructed.

a) $Z n | Z n^{2 +} | | C u^{2 +} | C u$

b) $Z n | Z n^{2 +} | | A g^{+} | A g$

c) $C u | C u^{2 +} | | A g^{+} | A g$

What is the correct order $E {^{0}}_{c e l l}$ of these cells?

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