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Ionic Radii and Ionisation Enthalpy (Group 2)

Identify the ...

Question

Identify the correct order of solubility of ${N a}_{2} S, C u S a n d Z n S$ in aqueous medium.

C u S > Z n S > {N a}_{2} S

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Z n S > {N a}_{2} S > C u S

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{N a}_{2} S > C u S > Z n S

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{N a}_{2} S > Z n S > C u S

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Solution

The correct option is D ${N a}_{2} S > Z n S > C u S$
$\begin{matrix} {N a}_{2} S is highly electrovalent i.e. gets easily dissociated into {N a}^{+} and s^{2 -} . so, it will have high solubility. \end{matrix}$
$Among C u S and Z n S, CuS has lesser K_{sp} than Z n S because$
$of which CuS (black) precipitates earlier than ZnS (greenish of white)$
$so, correct order of solubility$
${N a}_{2} S > Z n S > C u S$

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{N a}_{2} S, C u S

Z n S

C u S (I), Z n S (I I)

N a_{2} S (I I I)

The cell representation of the given reaction is:
Zn(s) + Cu²⁺ → Zn²⁺ + Cu(s)

The standard reducation potentials of

$Z n^{2 +} | Z n, C u^{2 +} | C u$ and $A g^{+} | A g$

are respectively -0.76, 0.34 and 0.8 V. The following cells were constructed.

a) $Z n | Z n^{2 +} | | C u^{2 +} | C u$

b) $Z n | Z n^{2 +} | | A g^{+} | A g$

c) $C u | C u^{2 +} | | A g^{+} | A g$

What is the correct order $E {^{0}}_{c e l l}$ of these cells?

Z n S

H_{2} S

{Z n S O}_{4}

P b S

{Z n (O H)}_{2}

{N a}_{2} {Z n O}_{2}

{N a}_{2} [{Z n (O H)}_{4}]

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