Identify the substance underlined: A dilute mineral acid that forms a white precipitate when treated with barium chloride solution.

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Solution

Dilute $H_{2} S O_{4}$ forms a white precipitate $(B a S O_{4})$ when treated with barium chloride $(B a C l_{2})$ solution.

Equation:

$B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + 2 H C l$

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Q. The questions (i) to (v) refer to the following salt solutions listed (a) to (f):
(a) Copper nitrate
(b) Iron (II) sulphate
(c) Iron (III) chloride
(d) Lead nitrate
(e) Magnesium sulphate
(f) Zinc chloride

(i) Which two solutions will give a white precipitate when treated with dilute hydrochloric acid followed by barium chloride solution?
(ii) Which two solution will give a white precipitate when treated with dilute nitric acid followed by silver nitrate solution?
(iii) Which solution will give a white precipitate when either dilute hydrochloric acid or dilute sulphuric acid is added to it?
(iv) Which solution becomes a deep/inky blue colour when excess of ammonium hydroxide is added to it?
(v) Which solution gives a white precipitate with excess ammonium hydroxide solution?

Q. The questions (i) to (v) refer to the following salt solutions listed A to F:
A. Copper nitrate
B. Iron (II) sulphate
C. Iron (III) chloride
D. Lead nitrate
E. Magnesium sulphate
F. Zinc chloride
(i) Which two solutions will give a white precipitate when treated with dilute hydrochloric acid followed by barium chloride solution?
(ii) Which two solutions will give a white precipitate when treated with dilute nitric acid followed by silver nitrate solution?
(iii) Which solution will give a white precipitate when either dilute hydrochloric acid or dilute sulphuric acid is added to it?
(iv) Which solution becomes a deep/inky blue colour when excess of ammonium hydroxide is added to it?
(v) Which solution gives a white precipitate with excess ammonium hydroxide solution?

Identify the following substance that is underlined: A dilute mineral acid which forms a white precipitate when treated with barium chloride solution.

Identify the following substance which are underlined:

(i) A dilute mineral acid that forms a white precipitate when treated with barium chloride solution.

Q. A dilute mineral acid, which forms a white precipitate when treated with barium chloride solution is :

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Preparation of Sulphuric Acid: Contact Process

Standard X Chemistry

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Identify the substance underlined: A dilute mineral acid that forms a white precipitate when treated with barium chloride solution.

Dilute H2SO4 forms a white precipitate (BaSO4) when treated with barium chloride (BaCl2) solution. Equation: BaCl2+H2SO4→BaSO4+2HCl

Dilute $H_{2} S O_{4}$ forms a white precipitate $(B a S O_{4})$ when treated with barium chloride $(B a C l_{2})$ solution.

Equation:

$B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + 2 H C l$