If $0.5$ mole of $B a C l_{2}$ is mixed with $0.2$ mole of $N a_{3} P O_{4}$ , the maximum number of moles of $B a_{3} (P O_{4})_{2}$ that can be formed is

0.70

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.50

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.20

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.10

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $0.10$
The balanced reaction is
$3 B a C l_{2} + 2 N a_{3} P O_{4} \to B a_{3} (P O_{4})_{2} + 6 N a C l$
In this reaction, $3$ moles of $B a C l_{2}$ combines with $2$ moles of $N a_{3} P O_{4}$ .
Hence $0.5$ mole of $B a C l_{2}$ recquire $= \frac{2}{3} \times 0.5 = 0.33$ moles of $N a_{3} P O_{4}$ .
Since, available $N a_{3} P O_{4}$ $(0.2$ mole $)$ is less than required mole $(0.33)$ , it is the limiting reactant and would determine the amount of product $B a_{3} (P O_{4})_{2}$ .
$∴ 2$ moles of $N a_{3} P O_{4}$ gives $1$ mole of $B a_{3} (P O_{4})_{2}$ .
$∴ 0.2$ mole of $N a_{3} P O_{4}$ would give $= \frac{1}{2} \times 0.2 = 0.1$ mole $B a_{3} (P O_{4})_{2}$

Suggest Corrections

164

Similar questions

Q. 0.5 mole

B a C l_{2}

is mixed with 0.2 mole

N a_{3} P O_{4}

, the maximum number of moles of

B a_{3} (P O_{4})_{2}

that can be formed is :

Q. If 0.5 moles of

B a C l_{2}

is mixed with 0.2 moles of

N a_{3} P O_{4},

the maximum number of moles of

B a_{3} (P O_{4})_{2}

that can be formed is:
The corresponding balanced reaction is:

3 B a C l_{2} + 2 N a_{3} P O_{4} \to B a_{3} (P O_{4})_{2} + 6 N a C l

If $0.5 m o l e$ of $B a C l_{2}$ is mixed with $0.2 m o l e$ of $N a_{3} P O_{4}$ , the maximum number of moles of $B a_{3} (P O_{4})_{2}$ formed are

Q. If 0.5 moles of

B a C l_{2}

is mixed with 0.2 moles of

N a_{3} P O_{4},

the maximum number of moles of

B a_{3} (P O_{4})_{2}

that can be formed is:
The corresponding balanced reaction is:

3 B a C l_{2} + 2 N a_{3} P O_{4} \to B a_{3} (P O_{4})_{2} + 6 N a C l

Q. If 0.5 moles of

B a C l_{2}

is mixed with 0.1 moles of

N a_{3} P O_{4},

the maximum amount of

B a_{3} (P O_{4})_{2}

that can be formed is

Join BYJU'S Learning Program

If 0.5 mole of BaCl2 is mixed with 0.2 mole of Na3PO4, the maximum number of moles of Ba3(PO4)2 that can be formed is

If $0.5$ mole of $B a C l_{2}$ is mixed with $0.2$ mole of $N a_{3} P O_{4}$ , the maximum number of moles of $B a_{3} (P O_{4})_{2}$ that can be formed is