Question

If $(1-p)$ is a root of quadratic equation $x^2+px+1(1-p)=0$, then its roots are

• A. $0,1$
• B. $-1,2$
• C. $0,-1$
• D. $-1,1$

Answer 1

The correct option is C $0,-1$

Since (1-P) is the root of quadratic equation, then it would satisfy the equation $x^2+Px+1(1-P)=0$

$\Rightarrow (1-P{)}^2+P(1-P)+1(1-P)=0$

$\Rightarrow 1+p^2-2P+P-P^2+1-P=0$

$\Rightarrow 2P=2\Rightarrow P=1$

$e{q}^n\Rightarrow x^2+x=0$

$\Rightarrow x(x+1)=0$

Roots $=0,-1$