If (1-p) is a root of quadratic $x^{2} + p x + 1 (1 - p) = 0$ , then its roots are

0, 1

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-1, 2

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0, -1

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-1, 1

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Solution

The correct option is A 0, 1
We have,
$x^{2} + p x + 1 (1 - p) = 0$

Since, root are $(1 - p)$ and $α$

Therefore,
$1 - p + α = - p$ and $(1 - p) α = 1 - p$
$⟹ α = 1$
$⟹ p = 1$
$⟹ 1 - p = 0$

Hence, roots are $(0, 1)$

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