If $12$ boxes are required to hold $48$ liters of milk, then :
_____ boxes are required to hold $60$ liters of milk.

Open in App

Solution

Given that,
$12$ boxes are required to hold $48$ liters of milk
Assume, $x$ boxes are required to hold $60$ liters of milk.
In proportion it can be written as
$12 : x : : 48 : 60$
Therefore,
$\frac{12}{x} = \frac{48}{60} x = \frac{12 \times 60}{48} x = 15$
Hence, $15$ boxes are required to hold $60$ liters of milk

Suggest Corrections

Similar questions

If $12$ boxes are required to hold $48$ liters of milk, then :

$36$ boxes will be required to hold _____ liters of milk.

Four containers can hold $101 l i t e r s$ of milk .

(a)how much milk will $7$ containers hold

Four containers can hold $101$ liters of milk .

(b)How many containers will hold $252.5$ liters of milk ?

A glass contains $\frac{1}{4}$ liter of milk. How many glasses of milk is required to fill a bucket of $\frac{10}{2}$ liters ?
[4 MARKS]

10.5 c m

Join BYJU'S Learning Program