If $2^{n + 1} = 8$ , what is the value of $n$ ?

1

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2

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3

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\frac{1}{2}

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Solution

The correct option is B $2$
Given, $2^{n + 1} = 8$
$\Rightarrow 2^{n + 1} = 2^{3}$
$∵$ Base are same
$∴ n + 1 = 3$
$\Rightarrow n = 3 - 1 = 2$

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