If 3-01- 1020 molecules are removed from 98 mg of H 2 SO 4 then no- Of moles of H 2 SO 4 left are-

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If 3.01* 1020...

Question

If 3.01*10²⁰ molecules are removed from 98mg of H₂SO₄ then no. Of moles of H₂SO₄ left are?

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Solution

Molecular mass of H2SO4=2+32+64=98gm

98 gm of sulphuric acid will contain 6.0210^23 molecule.

1 gm = 1000 mg

So 1 mg = 1/1000 gm

So 98 mg of sulphuric acid will contain 6.0210^20 molecule

Total molecule present initially equal to 6.0210^20 molecule

3.0110^20 molecule removed so molecule remained = Total molecule - molecule removed

= 6.0210^20 -3.0110^20

= 3.0110^20 molecule will remain

6.0210^23 molecule = 1 mole

1 molecule = 1/(6.0210^23) mole

3.0110^20 molecule = (3.0110^20)/ (6.0210^23)

= 1/2000 mole = .0005 mole

0.0005 moles of H2SO4 are left

Answer : 0.0005 mole or 5*10^(-4) mole

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If 3.01*1020 molecules are removed from 98mg of H2​​​​​SO4 then no. Of moles of H2SO​​​4 left are?

If 3.01*10²⁰ molecules are removed from 98mg of H₂SO₄ then no. Of moles of H₂SO₄ left are?