Question

If $378$ coins consist of one rupee, $50$ paise and $25$ paise coins whose values are in the ratio $13:11:7,$ then the number of $50$ paise coins will be

• A. $132$
• B. $128$
• C. $136$
• D. $133$

Answer 1

Answer: (A)

$132$

Let, Number of one-rupee coins = x,
Number of 50 paise coins = y,
Number of 25 paise coins = z,
Given, x + y + z = 378 ....... (1)
Also, $1\times x:\frac{50}{100}\times y:\frac{25}{100}\times z=13:11:7$
$\Rightarrow x:y/2:z/4=13:11:7$
$\Rightarrow \frac{x}{13}=\frac{y/2}{11}=\frac{z/4}{7}=k$ (say)
$\Rightarrow x=13k,y=22k,z=28k.$
Then, $13k+22k+28k=378$ (From (1))
$\Rightarrow 63k=378$ hence $k=6$
$\therefore$ Number of 50 paise coins $=22\times 6=132$