Question

If $8$ coins are tossed, what is the chance that one and only one will turn up head?

Answer 1

$8$ coins are tossed

So possible number of outcomes $=2^8=256$

There can be head on either first , second , third.....eight coin.

So there are $8$ possible ways in which a head can come

$\therefore$ Required probability $=\frac{8}{2^8}=\frac{1}{32}$