Question

If $9y^2-3y-2=0$, then $y=-\frac{2}{3},\frac{1}{3}$.

• A. Yes
• B. No
• C. Ambiguous
• D. Data insufficient

Answer 1

The correct option is B No

Given equation is:

$9y^2-3y-2=0$
$9y^2-6y+3y-2=0$
$(3y-2)(3y+1)=0$

$\therefore y=\frac{2}{3},\frac{-1}{3}$