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Question

If a, b, c are all positive and not all equal then the value of the determinant abcbcacab is

A
0
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B
< 0
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C
> 0
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D
cannot be determined
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Solution

The correct option is B < 0
Let |A|=∣ ∣abcbcacab∣ ∣

C1C1+C2+C3
|A|=∣ ∣a+b+cbca+b+ccaa+b+cab∣ ∣

=(a+b+c)∣ ∣1bc1ca1ab∣ ∣
R1R1R2,R2R2R3
=(a+b+c)∣ ∣0baca0caab1ab∣ ∣

=(a+b+c)[(ba)(ab)(ca)2]
|A|=(a+b+c)[(ab)2+(ca)2]
Now, (ab)2,(ca)2>0 and a+b+c>0 as a,b,c>0
|A|<0
Hence, ∣ ∣abcbcacab∣ ∣<0

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