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Standard XII

Physics

2nd Equation of Motion

If a body sta...

Question

If a body starts from rest and travels 120 m in the 8 $^{t h}$ second, assuming acceleration is constant during its journey, then its value is:

16 m / s^{2}

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10 m / s^{2}

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0.227 m / s^{2}

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0.03 m / s^{2}

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Solution

The correct option is A $16 m / s^{2}$
$S_{n^{t h}} = u + \frac{a}{2} (2 n - 1)$
$\Rightarrow 120 = S_{8^{t h}} = 0 + \frac{a}{2} (2 \times 8 - 1)$
$\Rightarrow a = \frac{240}{15} = \frac{80}{5} = 16 m / s^{2}$

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If a body starts from rest and travels 120 m in the 8th second, assuming acceleration is constant during its journey, then its value is:

The correct option is A 16 m/s2Snth=u+a2(2n−1)⇒120=S8th=0+a2(2×8−1)⇒a=24015=805=16m/s2

If a body starts from rest and travels 120 m in the 8 $^{t h}$ second, assuming acceleration is constant during its journey, then its value is:

The correct option is A $16 m / s^{2}$
$S_{n^{t h}} = u + \frac{a}{2} (2 n - 1)$
$\Rightarrow 120 = S_{8^{t h}} = 0 + \frac{a}{2} (2 \times 8 - 1)$
$\Rightarrow a = \frac{240}{15} = \frac{80}{5} = 16 m / s^{2}$