If a current I given by I 0sin- t -2 flows in an ac circuit across which an ac potential of E - E 0sin- t has been applied- then the power consumption P in the circuit will be A- P - E 0 I 0-2B- P -0C- P -2 E 0 I 0D- P - E 0 I 0-2

The correct option is B P = 0Phase angle ϕ = 90^∘, so power P = Vi cos ϕ = 0 ...

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Power Factor

If a current ...

Question

If a current I given by $I_{0} s i n (ω t - \frac{π}{2})$ flows in an ac circuit across which an ac potential of $E = E_{0} s i n ω t$ has been applied, then the power consumption P in the circuit will be

P = \frac{E_{0} I_{0}}{\sqrt{2}}

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P = \sqrt{2} E_{0} I_{0}

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P = \frac{E_{0} I_{0}}{2}

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P = 0

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I

I = I_{0} sin (ω t - π / 2)

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I_{0} sin (ω t - π / 2)

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