Question

If $A$ is the area under the graph of the intensity magnetization in ferromagnetic material versus magnetizing field intensity, $V$ is the volume of the magnetic sample and $n$ is the frequency of alternating magnetic field , then the rate of hysteresis loss in the substance is

• A.
  $A$
• B.
  $AVn$
• C.
  $\frac{AV}{n}$
• D.
  $\frac{A}{nV}$

Answer 1

The correct option is B

$AVn$
Area of hysterisis loop gives the loss of energy per unit volume of material in one cycle of magnetization and de-magnetization.

So, Total loss per unit time will be represented by,

$\text{Area}\times \text{volume}\times \text{Frequency}$

Rate of hysteresis loss $=AVn$

Hence, option $\left(B\right)$ is the correct answer.

Why this Question? Tip: Area of hysterisis loop gives the loss of energy per unit volume of material in one cycle of magnetization and de-magnetization.