Question

If a spring extends by $x$ on loading then energy stored by the spring is:- ($T$ is the tension in the spring, $k$ is spring constant)

• A. $\frac{T^2}{2x}$
• B. $\frac{T^2}{2k}$
• C. $\frac{2k}{T^2}$
• D. $\frac{{2T}^2}{k}$

Answer 1

The correct option is B $\frac{T^2}{2k}$

T=kx

Energy =$\frac{1}{2}\times k{x}^2$

Energy=$\frac{1}{2}\frac{T^2}{k}$