Question

If $A=\tan 1,B=\tan 2$ and $C=\tan 3,$ then the descending order of $A,B$ and $C$ is

• A. $A,B,C$
• B. $C,B,A$
• C. $A,C,B$
• D. $B,C,A$

Answer 1

The correct option is C $A,C,B$

$1\text{radian}={\left(\frac{180}{\pi }\right)}^{\circ }\approx {57}^{\circ }{18}^{\prime }$
$2\text{radian}\approx {114}^{\circ }{36}^{\prime }$
$3\text{radian}\approx {171}^{\circ }{53}^{\prime }$


From graph, $A>C>B$