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Question

If ax=by=cz=abc, then 1x+1y+1z=__

A
-1
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B
xyz
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C
1
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D
1xyz
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Solution

The correct option is C 1
ax=by=cz=abc
ax=abca=(abc)1/x ___ (1)
by=abcb=(abc)1/y ___ (2)
cz=abcc=(abc)1/z ___ (3)
Multiply (1), (2), (3)
abc=(abc)(1x+1y+1z)
1x+1y+1z=1
(Comparing coff.)

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