If AB is a chord of a circle with center O, and AC=BC, then x=90∘.
90°
80°
We know that the segment joining the centre of a circle and the midpoint of its chord is perpendicular to the chord. Hence, x=90∘.
If AB,BC, and CD are equal chords of a circle with O as center, and AD diameter then ∠AOB equals to
If AB is a chord of a circle with center O, then x=90∘
If AB is a chord of a circle with centre O. Then ∠x=90∘.