wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If cosecc θ = 10 then sec θ = ?

(a) 310 (b) 103 (c) 110 (d) 210

Open in App
Solution

ABC is a right-angled triangle.

Given: cosec θ=10

But sinθ=1cosecθ=110

Also, sinθ=Opposite sideHypotenuse side=BCACBCAC=110

Thus BC=k and AC=10k

Using Pythagoras theorem in ABC, we have,

AC2=AB2+BC2AB2=AC2BC2AB2=(10k)2(k)2AB2=9k2AB=3ksec θ=ACAB=10k3k=103


flag
Suggest Corrections
thumbs-up
5
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Trigonometric Ratios
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon