If 5x-1x-2x-1-Ax-2-Bx-1- then 3B is equal to

The correct option is B 2A Given, 5x+1(x+2)(x 1)=Ax+2+Bx 1 Making denominators same on both sides of the equation, 5x+1 = A(x 1) + B(x+2) #16 ...

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Parametric Differentiation

If 5x+1x+2x...

Question

If $\frac{5 x + 1}{(x + 2) (x - 1)} = \frac{A}{x + 2} + \frac{B}{x - 1}$ , then $3 B$ is equal to

A

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2 A

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3 A

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4 A

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Solution

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Similar questions

x = {log}_{2 a} a, y = {log}_{3 a} 2 a a n d z = {log}_{4 a} 3 a

x y z + 1 =

\frac{x^{2} + 5 x + 1}{(x + 1) (x + 2) (x + 3)} = \frac{A}{x + 1} + \frac{B}{(x + 1) (x + 2)}

+ \frac{C}{(x + 1) (x + 2) (x + 3)},

B

(x^{5} + 1), (3 - x^{4}), (4 + x^{3} + x^{6})

-

(2 a^{3} - 3 b^{5}), (2 a^{3} + 3 b^{5}), (2 a^{4} - 3 a^{2} b^{2} + b^{4})

f (x) =

∣ ∣ ∣ ∣ ∣ \begin{matrix} (1 + 3 x)^{2 a} & (1 + 2 x)^{3 b} & 1 1 & (1 + 3 x)^{2 a} & (1 + 2 x)^{3 b} (1 + 2 x)^{3 b} & 1 & (1 + 3 x)^{2 a} \end{matrix} ∣ ∣ ∣ ∣ ∣

I = \int x s i n^{- 1} {\frac{1}{2} \sqrt{\frac{2 a - x}{a}}} d x = \frac{A}{248} (x^{2} - 2 a^{2}) c o s^{- 1} \frac{x}{2 a} - \frac{1}{8} x \sqrt{4 a^{2} - x^{2}} + C

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