If xy+yx=2,x≠0,y≠0, find x3−y3.
If xy+yx=−1, where x,y≠0 then the value of (x3−y3) is (a) 1
(b)−1
(c) 0
(d) 12
If xy+yx=−1 (x,y≠0), find the value of x3−y3