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B
0
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C
1
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D
None of these
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Solution
The correct option is C 1 Given ∣∣∣α−β1−¯αβ∣∣∣ =∣∣
∣∣(α−β)¯ββ(1−¯αβ)∣∣
∣∣ =|α−β|∣∣¯β∣∣∣∣¯β−¯α∣∣...(∵β¯β=∣∣¯β∣∣2)=∣∣β2∣∣=1) =|α−β||β|∣∣¯¯¯¯¯¯¯¯¯¯¯¯¯β−α∣∣ =|α−β||β−α|(∵|¯z|=|z|)=1