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Question

If ω is an imaginary cube root of unity then (1+ωω2)7 equals

A
128ω
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B
128ω
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C
128ω2
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D
128ω2
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Solution

The correct option is C 128ω2
ω is the cube root of unity, implies 1+ω+ω2=0
ω2=1ω
Thus, the expression can be simplified as
(1+ωω2)7=(2ω2)7
=27ω14
=128ω2

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