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Question

If a=^i+^j+^k & b=^j^k, then the vector c such that a.c=3 & a×c=b is

A
13(3^i2^j+5^k)
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B
13(5^i+2^j+2^k)
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C
13(^i+2^j5^k)
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D
13(3^i+2^j+^k)
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Solution

The correct option is B 13(5^i+2^j+2^k)
a=(1,1,1)b=(0,1,1)
Let,
c=(x,y,z)ac=3x+y+z=3(1)a×c=b(zy)^i+(xz)^j+(yx)^k=^j^kz=y(2);xz=1(3);yx=1(4)
Solving (1) ,(2) ,(3) and (4) we get:
x=53,y=23,z=23

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