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Byju's Answer
Standard XII
Chemistry
EMF
If E0Fe2+/F...
Question
If
E
0
F
e
2
+
/
F
e
=
−
0.441 V and
E
0
F
e
3
+
/
F
e
2
+
= 0.771 V, the standard
E
M
F
of the reaction,
F
E
+
2
F
E
3
+
→
3
F
E
2
+
will be:
A
0.330
V
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B
1.653
V
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C
1.212
V
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D
0.111
V
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Solution
The correct option is
C
1.212
V
F
e
→
F
e
+
2
+
2
e
−
E
0
F
e
/
F
e
2
+
2
F
e
+
3
+
2
e
−
→
2
F
e
+
2
E
0
F
e
3
+
/
F
e
2
+
The above are the half cell reaction for the cell.
From here we can observe
E
o
c
e
l
l
=
E
o
F
e
/
F
e
+
2
+
E
o
F
e
+
3
/
F
e
+
2
=
−
(
−
0.441
)
+
(
0.771
)
=
1.212
V
Hence, the correct option is
C
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0
Similar questions
Q.
If
E
0
F
e
2
+
/
F
e
=
−
0.441
V
and
E
0
F
e
3
+
/
F
e
2
+
=
0.771
V
, the standard emf of the reaction
F
e
+
2
F
e
3
+
→
3
F
e
2
+
will be:
Q.
Given,
E
0
F
e
3
+
/
F
e
=
0.036
V
,
E
0
F
e
2
+
/
F
e
=
−
0.439
V
. The value of standard electrode potential for the change,
F
e
3
+
(
a
q
)
+
e
−
→
F
e
2
+
(
a
q
)
will be :
Q.
If
E
o
F
e
2
+
/
F
e
=
−
0.441
V
and
E
o
F
e
3
+
/
F
e
2
+
=
0.771
V
;then
E
o
for the reaction
F
e
+
2
F
e
3
+
→
3
F
e
2
+
will be
Q.
Given the standard oxidation potentials:
E
0
F
e
(
s
)
/
F
e
2
+
(
a
q
)
=
0.44
V
E
0
F
e
2
+
(
a
q
)
/
F
e
3
+
(
a
q
)
=
−
0.77
V
The standard EMF of the given reaction will be:
F
e
(
s
)
+
2
F
e
3
+
(
a
q
)
→
3
F
e
2
+
(
a
q
)
Q.
Calculate
E
c
e
l
l
for :
F
e
(
s
)
|
F
e
2
+
(
0.1
M
)
|
|
F
e
3
+
(
0.01
M
)
|
F
e
2
+
(
1
M
)
|
P
t
, T = 298 K.
Given
E
0
F
e
3
+
/
F
e
2
+
=
+
0.771
V
,
E
0
F
e
2
+
/
F
e
=
−
0.41
V
.
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