If E0Fe2-Fe - - 0-441 V and E0Fe3-Fe2- - 0-771 V- the standard EMF of the reaction- FE - 2FE3- 3FE2- will be-

The correct option is C 1.212 V Fe → Fe^ +2 +2e^ E^ 0 _ Fe/Fe^ 2+ #160; 2Fe^ +3 +2e^ → 2Fe^ +2 E^ 0 _ Fe^ 3+ /Fe^ 2+ The above ...

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EMF

If E0Fe2+/F...

Question

If $E_{F e^{2 +} / F e}^{0}$ = $-$ 0.441 V and $E_{F e^{3 +} / F e^{2 +}}^{0}$ = 0.771 V, the standard $E M F$ of the reaction,
$F E + 2 F E^{3 +} \to 3 F E^{2 +}$ will be:

0.330 V

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1.653 V

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1.212 V

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0.111 V

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Solution

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Similar questions

E_{F e^{2 +} / F e}^{0} = - 0.441 V

E_{F e^{3 +} / F e^{2 +}}^{0} = 0.771 V

F e + 2 F e^{3 +} \to 3 F e^{2 +}

E_{F e^{3 +} / F e}^{0} = 0.036 V, E_{F e^{2 +} / F e}^{0} = - 0.439 V

F e^{3 +} (a q) + e^{-} \to F e^{2 +} (a q)

E_{F e^{2 +} / F e}^{o} = - 0.441 V

E_{F e^{3 +} / F e^{2 +}}^{o} = 0.771 V

E^{o}

F e + 2 F e^{3 +} \to 3 F e^{2 +}

E_{F e (s) / F e^{2 +} (a q)}^{0} = 0.44 V

E_{F e^{2 +} (a q) / F e^{3 +} (a q)}^{0} = - 0.77 V

F e (s) + 2 F e^{3 +} (a q) \to 3 F e^{2 +} (a q)

E_{c e l l}

F e_{(} s) | F e^{2 +} (0.1 M) | | F e^{3 +} (0.01 M) | F e^{2 +} (1 M) | P t

E_{F e^{3 +} / F e^{2 +}}^{0} = + 0.771 V, E_{F e^{2 +} / F e}^{0} = - 0.41 V

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