If f(x) = 3x - 4, then $f^{- 1} =$

\frac{y + 4}{3}

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\frac{y - 4}{3}

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\frac{y - 3}{4}

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\frac{y + 3}{4}

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Solution

The correct option is A $\frac{y + 4}{3}$
$f (x) = 3 x - 4$ (Given)
Say, $y = 3 x - 4$
$\Rightarrow 3 x = y + 4 \Rightarrow x = \frac{(y + 4)}{3} ∴ f^{- 1} (x) = x = \frac{y + 4}{3}$

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Similar questions

Letbe a function defined as. The inverse of f is map g: Range

(A) (B)

Let $f : R - {- \frac{4}{3}} \to R$ be a function defined as $f (x) = \frac{4 x}{3 x + 4}, x \neq - \frac{4}{3}$ . The inverse of f is the map g: Range $f \to R - {- \frac{4}{3}}$ is given by
$(a) g (y) = \frac{3 y}{3 - 4 y} (b) g (y) = \frac{4 y}{4 - 3 y} (c) g (y) = \frac{4 y}{3 - 4 y} (d) g (y) = \frac{3 y}{4 - 3 y}$

Q. The intercept form of the line

3 x - 4 y + 12 = 0

Q. Find the value of

(x + y)^{4}

using Pascal's triangle.

Q. Simplify:

(4^{y} + 4^{y} + 4^{y} + 4^{y}) (3^{y} + 3^{y} + 3^{y})

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If f(x) = 3x - 4, then f−1=

The correct option is A y+43f(x)=3x−4 (Given)Say, y=3x−4⇒3x=y+4⇒x=(y+4)3∴f−1(x)=x=y+43

If f(x) = 3x - 4, then $f^{- 1} =$

The correct option is A $\frac{y + 4}{3}$
$f (x) = 3 x - 4$ (Given)
Say, $y = 3 x - 4$
$\Rightarrow 3 x = y + 4 \Rightarrow x = \frac{(y + 4)}{3} ∴ f^{- 1} (x) = x = \frac{y + 4}{3}$