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Question

If f(x)=(4sinxcos2x) the find the 7th derivative of f(x).

A
37cos3x+cosx
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B
37cos3x+cosx
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C
37(cos3x+cosx)
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D
37(cos3x+cosx)
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Solution

The correct option is B 37cos3x+cosx
f(x)=4cos2xsinx

=2sin2xcosx
2sinacosb=sin(a+b)+sin(ab)

f(x)=sin3x+sinx
f1(x)=3cos3xcosx
f11(x)=3sin3xsinx
f111(x)=33cos3x+sinx
.
.
.
f7(x)=37cos3x+cosx

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