Question

If $f\left(x\right)=x^3-3x^2+3x-4$, find $f\left(2\right)+f(-2)$

Answer 1

Given $f\left(x\right)=x^3-3x^2+3x-4$

Therefore, $f\left(2\right)=2^3-3\left(2^2\right)+3\left(2\right)-4$

$⟹f\left(2\right)=8-12+6-4=14-16=-2$

$f(-2)=(-2{)}^3-3(-2{)}^2+3(-2)-4$

$⟹f\left(2\right)=-8-12-6-4=-30$

Therefore, $f\left(2\right)+f(-2)=-2-30=-32$