Question

If five dice are thrown simultaneously, then what is the probability of getting the sum of the numbers as seven?

• A. 15/(6⁵)
• B. 10/(6⁵)
• C. 15/(5⁶)
• D. 10/(5⁶)
• E. None of these

Answer 1

The correct option is A

15/(6⁵)

The following are the two cases when the sum will be 7:

7 = 1+1+1+1+3 = ${}^5$C${}_1$ways = 5

7 = 1+1+1+2+2 = ${}^5$C${}_2$ways = 10

Total number of possible ways of throwing five dice = 6${}^5$

Therefore, required probability = 15/$\left(6^5\right)$