Question

If $\frac{2}{3},k,\frac{5k}{8}$ are in A.P. then $k=$

Answer 1

Given $\frac{2}{3},k,\frac{5k}{8}$ are in $AP$

$⟹2k=\frac{2}{3}+\frac{5k}{8}$

$⟹2k-\frac{5k}{8}=\frac{2}{3}$

$⟹\frac{11k}{8}=\frac{2}{3}$

$⟹k=\frac{16}{33}$