Question

If HCF of numbers $408$ and $1032$ can be expressed in the form of $1032x-408\times 5$, then find the value of $x$.

• A. $0$
• B. $1$
• C. $2$
• D. $3$

Answer 1

Answer: (C)

$2$

$408=2\times 2\times 2\times 3\times 17$

$1032=2\times 2\times 2\times 3\times 43$

Hence, $HCF=2\times 2\times 2\times 3=24$

Now, $1032x-408\times 5=24\Rightarrow 1032x=2064\Rightarrow x=2$