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Coupled circuits-1

If i2=2cos 50...

Question

If $i_{2} = 2 cos 500 t$ A in the network given below, then the value of the maximum energy stored in the network is

A

18 J

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B

16 J

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C

6 J

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D

42 J

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Solution

The correct option is A 18 J
$L_{e q} = 4 + 5 + 6 - (2 \times 3) = 9 H$

Energy stored maximum $= \frac{1}{2} L_{e q} i_{2}^{2} = \frac{1}{2} \times 9 \times 2^{2} = 18 J$

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