CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Definition of Functions

If I=∫ 0 1 ...

Question

If $I = \int_{0}^{1} \frac{x}{8 + x^{3}} d x$ , then the smallest interval is which $I$ lies is

A

(0, \frac{1}{8})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

(0, \frac{1}{9})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

(0, \frac{1}{10})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

(0, \frac{1}{7})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $(0, \frac{1}{9})$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The value of the definite integral

\int_{0}^{1} \frac{x d x}{x^{3} + 16}

lies in the interval [a, b]. The smallest such interval is.

x ϵ R

m = \frac{x^{2}}{(x^{4} - 2 x^{2} + 4)}

, then m lies in the interval

x \in R

\frac{1}{x^{2} + 4 x + 9}

lies in the interval

x ϵ R

m = \frac{x^{2}}{(x^{4} - 2 x^{2} + 4)}

, then m lies in the interval

x < 2

\frac{1}{x}

lies in the interval

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Definition of Function

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Definition of Functions

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon