If xy - yx - -1 x- y - 0- the value of x3 - y3 is-

The correct option is C 0 Given: x/y +y/x = 1 ∴x^2 + y^2/xy = 1 x^2 + y^2 + xy =0 ...(i)The equation, x^3 y^3 = (x y)(x^2 + xy + y ...

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Derivative of Standard Functions

If xy + yx ...

Question

If $(\frac{x}{y} + \frac{y}{x} = - 1) (x, y \neq 0),$ the value of $(x^{3} - y^{3})$ is,

1

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\frac{1}{2}

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\frac{x}{y} + \frac{y}{x} = - 1, (x, y \neq 0)

x^{3} - y^{3}

\frac{x}{y} + \frac{y}{x} = - 1 (x, y \neq 0)

x^{3} - y^{3}

If $\frac{x}{y} + \frac{y}{x} = - 1$ , where $x, y \neq 0$ then the value of $(x^{3} - y^{3})$ is
(a) $1$

(b) $- 1$

(d) $\frac{1}{2}$

\frac{x}{y} + \frac{y}{x} = - 1

x, y \neq 0

x^{3} - y^{3}

\frac{1}{2}

\frac{x}{y} + \frac{y}{x} = - 1

x, y \neq 0

x^{3} - y^{3}

\frac{1}{2}

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