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Byju's Answer
Standard XII
Mathematics
Implicit Differentiation
If log 0.5s...
Question
If
log
0.5
sin
x
=
1
−
log
0.5
cos
x
then number of values of
x
∈
[
−
2
π
,
2
π
]
is
A
1
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B
2
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C
3
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D
4
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Solution
The correct option is
D
4
log
0.5
cos
x
sin
x
=
1
cos
x
sin
x
=
1
2
2
sin
x
cos
x
=
1
sin
2
x
=
1
2
x
=
(
2
k
+
1
)
Π
2
N
o
.
o
f
v
a
l
u
e
s
o
f
x
s
a
t
i
s
f
y
i
n
g
=
4
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0
Similar questions
Q.
If log
0.
5
sinx = 1 - log
0.
5
cosx then number of values of
x
∈
[
−
2
π
,
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]
is
Q.
If
log
0.5
sin
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=
1
−
log
0.5
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, then the number of solutions of
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Q.
If
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0.5
sin
x
=
1
−
log
0.5
cos
x
, then the number of solutions of
x
in
−
2
π
≤
x
≤
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π
is
Q.
If
log
0.5
sin
x
=
1
−
log
0.5
cos
x
, then the number of solutions in the interval
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−
2
π
,
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π
]
is
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The solution of
log
0.5
cos
x
=
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, where
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−
2
π
,
2
π
]
is
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