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Quantitative Aptitude

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If log 2=0....

Question

If $log 2 = 0.3010$ and $log 3 = 0.4771$ , then the number of digits in $6^{17}$ is

A

12

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B

11

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C

14

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D

10

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Solution

The correct option is B $14$
Given,

$6^{17}$

applying log, we get,

$= 17 log 6$

$= 17 log (2 \times 3)$

$= 17 (log 2 + log 3)$

$= 17 (0.3010 + 0.4771)$ (given)

$= 13.22$

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