If magnification is positive, the nature of the image is:

real and inverted

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virtual and erect

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real

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none of these

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Solution

The correct option is B virtual and erect
Magnification is the ratio of the size of the image ( $h_{i}$ ) to the size of the object( $h_{o}$ )
M $= \frac{s i z e o f t h e i m a g e}{s i z e o f t h e o b j e c t}$
As per sign convention,the height of an inverted and real
image is negative and hence the magnification of a lens is negative
when it produces an inverted and real image. For an erect and virtual
image, the height of the image is positive. So, the magnification is
positive when an erect and virtual image is formed.

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