Question

If momentum of a photon of an electromagnetic radiation is $3.3\times {10}^{-29}$ kg m/sec, then frequency of associated wave is:

• A. $3.0\times {10}^{3}Hz$
• B. $6.0\times {10}^{3}Hz$
• C. $7.5\times {10}^{5}Hz$
• D. $1.5\times {10}^{13}Hz$

Answer 1

Answer: (D)

$1.5\times {10}^{13}Hz$

$p=\frac{hv}{c}$
$\Rightarrow v=\frac{cp}{h}=\frac{(3\times {20}^8)\times (3\cdot 3\times 10-29)}{6\cdot 6\times {10}^{-34}}$

$=1\cdot 5\times {10}^{13}Hz.$