If NaOH is added to an aqueous solution of zinc ions, a white precipitate appears and on adding excess NaOH, the precipitate dissolves. In this solution, zinc exists in the:
A
Cationic part
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B
Anionic part
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C
Both in the cationic and anionic parts
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D
Precipitate
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Solution
The correct option is B Anionic part The reaction occurs is: 2NaOH+Zn2+→Zn(OH)2(white ppt.)↓+2Na+
Zn(OH)2(white ppt.)+2NaOH→Na2[Zn(OH)4]
From the above reaction, it can be seen that zinc exists in the anionic part.