Question

If number of Bonding electrons = 10 and number of anti-bonding electrons = 8, the bond order for the corresponding molecule is ​​​​​​​.

• A. 1
• B. 2
• C. 3

Answer 1

The correct option is A 1

As we have seen in the earlier,

Bond order = $\frac{1}{2}$ [Bonding Electrons - Anti Bonding electrons]

Bond Order = $\frac{1}{2}$ [10 - 8] = 1