If ω is an imaginary cube root of unity, then (1+ω-ω2)7 equals
128ω
-128ω
128ω2
-128ω2
Explanation for the correct option
As we know that when ω is an imaginary cube root of unity then
ω3=1and1+ω+ω2=0 which can be rewritten as 1+ω=-ω2
Now, the given expression is (1+ω-ω2)7
∴1+ω-ω27=-ω2-ω27=-2ω27=-128ω14=-128ω34·ω2=-12814·ω2=-128ω2
Hence, the correct option is (D).