Question

If optical rotation produced by the compound (A) is $+{52}^{\circ }$, the one produced by compound (B) is:

• A. $-{52}^{\circ }$
• B. $+{52}^{\circ }$
• C. $0^{\circ }$
• D. Unpredictable

Answer 1

The correct option is A

$-{52}^{\circ }$

Since (A) and (B) are enantiomers, so specific rotation of B is $-{52}^{\circ }$ (because enantiomers have equal and opposite specific rotation).