If ordered pair is equal, find the value of x and y.
(x,y+2)=(2x-4,3y+8)

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Solution

(x,y+2)=(2x-4,3y+8)

Equating both the abscissa,
x = 2x-4
$\Rightarrow$ x = 4

Equating ordinates
y+2 = 3y+8
$\Rightarrow$ 2y = -6
$\Rightarrow$ y = -3

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